[SYMBOLIC INDEX] page=1
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^6] = 6z^5
N₂ + 3H₂ ⇌ 2NH₃
CH₄ + 2O₂ → CO₂ + 2H₂O
\oint_C \vec{F}\cdot d\vec{r} = 0
5ψ² + 4ψ + 4 = 0
det| 3 1 ; 1 4 | = 11
12β² + 5β + 7 = 0
∫₀^∞ e^(-y²) dy = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
det| 4 8 ; 4 5 | = -12
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
det| 8 2 ; 1 9 | = 70
det| 11 4 ; 6 12 | = 108
iħ ∂ψ/∂t = Ĥψ
λ = h/p
d/dβ [β^7] = 7β^6
∇ × E = −∂B/∂t
5t² + 8t + 1 = 0
det| 1 6 ; 4 2 | = -22
∇²z = 0
d/dt [t^11] = 11t^10
d/dφ [φ^8] = 8φ^7
4t² + 9t + 0 = 0
det| 9 3 ; 5 10 | = 75
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dy [y^9] = 9y^8
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\lim_{y\to 0} \frac{\sin y}{y} = 1
9n² + 5n + 5 = 0
det| 5 5 ; 1 6 | = 25
\lim_{n\to 0} \frac{\sin n}{n} = 1
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∇²α = 0
N₂ + 3H₂ ⇌ 2NH₃
λ = h/p
det| 9 5 ; 1 10 | = 85
det| 9 8 ; 2 10 | = 74
∑_{k=1}^{n} k = n(n+1)/2
F = ma
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∂ψ/∂y = 6ψ
e^{i\pi} + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 1 1 ; 0 2 | = 2
6n² + 4n + 4 = 0
F = G m₁m₂ / r²
9α² + 9α + 3 = 0
e^{i\pi} + 1 = 0
det| 11 1 ; 0 12 | = 132
12t² + 4t + 3 = 0
d/dβ [β^10] = 10β^9
∂φ/∂ω = 4φ
∫₀^∞ e^(-β²) dβ = √π / 2
F = ma
6n² + 2n + 5 = 0
∇²θ = 0
N₂ + 3H₂ ⇌ 2NH₃
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
8ψ² + 3ψ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 3 9 ; 2 4 | = -6
7r² + 9r + 5 = 0
iħ ∂ψ/∂t = Ĥψ
2ψ² + 3ψ + 6 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
det| 11 1 ; 4 12 | = 128
det| 4 2 ; 2 5 | = 16
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
10r² + 3r + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∂t/∂x = 1t
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
2H₂ + O₂ → 2H₂O
det| 8 7 ; 1 9 | = 65
8n² + 6n + 3 = 0
det| 10 7 ; 5 11 | = 75
4ψ² + 7ψ + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
N₂ + 3H₂ ⇌ 2NH₃
3t² + 5t + 3 = 0
6n² + 4n + 6 = 0
\frac{6}{4} \sum_{i=1}^{n} i^{2}
\frac{10}{6} \sum_{i=1}^{n} i^{2}
N₂ + 3H₂ ⇌ 2NH₃
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 10 4 ; 2 11 | = 102
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
det| 2 4 ; 6 3 | = -18
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
det| 5 7 ; 6 6 | = -12
5ω² + 1ω + 2 = 0
∂n/∂γ = 2n
F = G m₁m₂ / r²
N₂ + 3H₂ ⇌ 2NH₃
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 12 7 ; 3 13 | = 135
d/dφ [φ^7] = 7φ^6
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
det| 6 6 ; 2 7 | = 30
8n² + 4n + 3 = 0