Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:53Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-α²) dα = √π / 2
52K
det| 12 5 ; 4 13 | = 136
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 11 2 ; 5 12 | = 122
100K
det| 4 9 ; 7 5 | = -43
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
197K
det| 1 1 ; 3 2 | = -1
det| 4 6 ; 4 5 | = -4
262K
∑_{k=1}^{n} k = n(n+1)/2
196K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
299K