Symbolic Index /sym/7351be
id=9 · host=au.commstar.world · 2026-10-16 15:00Z
10β² + 1β + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
444K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-t²) dt = √π / 2
295K
e^{i\pi} + 1 = 0
d/dt [t^12] = 12t^11
395K
det| 10 3 ; 4 11 | = 98
312K
∑_{k=1}^{n} k = n(n+1)/2
140K