Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:23Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
det| 4 8 ; 3 5 | = -4
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\oint_C \vec{F}\cdot d\vec{r} = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
264K
∫₀^∞ e^(-θ²) dθ = √π / 2
276K
∇ × E = −∂B/∂t
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
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