Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:07Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 9 4 ; 1 10 | = 86
100K
det| 1 2 ; 7 2 | = -12
50K
det| 2 4 ; 4 3 | = -10
137K
det| 5 6 ; 4 6 | = 6
197K