Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:39Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
∇²α = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
90K
det| 5 6 ; 5 6 | = 0
∑_{k=1}^{n} k = n(n+1)/2
50K
∑_{k=1}^{n} k = n(n+1)/2
det| 2 6 ; 0 3 | = 6
137K
det| 7 4 ; 4 8 | = 40
197K
d/dn [n^5] = 5n^4
∑_{k=1}^{n} k = n(n+1)/2
262K
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
299K