Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:11Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
52K
det| 2 2 ; 6 3 | = -6
∫₀^∞ e^(-n²) dn = √π / 2
91K
d/dφ [φ^6] = 6φ^5
det| 2 4 ; 4 3 | = -10
100K
det| 7 4 ; 4 8 | = 40
50K
det| 10 3 ; 1 11 | = 107
det| 9 7 ; 3 10 | = 69
137K
det| 11 7 ; 4 12 | = 104
det| 2 7 ; 7 3 | = -43
262K
det| 6 7 ; 0 7 | = 42
det| 7 6 ; 2 8 | = 44
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∇²z = 0