Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:55Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
52K
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-α²) dα = √π / 2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 4 6 ; 4 5 | = -4
100K
det| 8 3 ; 4 9 | = 60
det| 7 4 ; 4 8 | = 40
137K
det| 1 2 ; 7 2 | = -12
197K
9x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
196K