Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:07Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
6ω² + 3ω + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-α²) dα = √π / 2
50K
det| 7 4 ; 4 8 | = 40
137K
det| 4 8 ; 3 5 | = -4
197K