Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 18:23Z
det| 11 8 ; 0 12 | = 132
N₂ + 3H₂ ⇌ 2NH₃
Fe₂O₃ + 3CO → 2Fe + 3CO₂
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
100K
CH₄ + 2O₂ → CO₂ + 2H₂O
2H₂ + O₂ → 2H₂O
F = ma
ω = 2πf
7γ² + 5γ + 5 = 0