Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 13:59Z
8θ² + 4θ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
52K
∇²α = 0
det| 5 6 ; 5 6 | = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
100K
∑_{k=1}^{n} k = n(n+1)/2
d/dn [n^5] = 5n^4
∫₀^∞ e^(-α²) dα = √π / 2
262K
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
218K
det| 8 2 ; 7 9 | = 58
299K
det| 7 5 ; 0 8 | = 56
det| 6 8 ; 4 7 | = 10