Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:16Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
det| 5 6 ; 1 6 | = 24
102K
∑_{k=1}^{n} k = n(n+1)/2
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
276K
∇ × E = −∂B/∂t
det| 10 5 ; 4 11 | = 90
257K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
250K
λ = h/p
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
46K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
164K