Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:28Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 4 6 ; 4 5 | = -4
50K
∑_{k=1}^{n} k = n(n+1)/2
262K
det| 7 4 ; 4 8 | = 40
196K