Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 18:51Z
det| 11 8 ; 0 12 | = 132
∫₀^∞ e^(-y²) dy = √π / 2
52K
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-n²) dn = √π / 2
50K
CH₄ + 2O₂ → CO₂ + 2H₂O
2H₂ + O₂ → 2H₂O
F = ma