Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:43Z
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^11] = 11z^10
244K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
52K
det| 12 5 ; 4 13 | = 136
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
100K
det| 4 9 ; 7 5 | = -43
det| 7 4 ; 4 8 | = 40
197K
det| 1 1 ; 3 2 | = -1
det| 12 9 ; 3 13 | = 129
\binom{n}{k} = \frac{n!}{k!(n-k)!}
218K
F = ma
CaCO₃ → CaO + CO₂