Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:36Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
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∇ × E = −∂B/∂t
∫₀^∞ e^(-α²) dα = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1