Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:42Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
∑_{k=1}^{n} k = n(n+1)/2
52K
det| 2 2 ; 6 3 | = -6
∫₀^∞ e^(-n²) dn = √π / 2
91K
d/dφ [φ^6] = 6φ^5
det| 7 4 ; 4 8 | = 40
100K
det| 10 3 ; 1 11 | = 107
det| 4 6 ; 4 5 | = -4
137K
∑_{k=1}^{n} k = n(n+1)/2
197K
∫₀^∞ e^(-φ²) dφ = √π / 2
218K