Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:53Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
244K
6ω² + 3ω + 2 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 7 4 ; 4 8 | = 40
50K
det| 8 2 ; 7 9 | = 58
197K
∑_{k=1}^{n} k = n(n+1)/2
262K