Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
102K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
264K
∇ × E = −∂B/∂t
\frac{11}{6} \sum_{i=1}^{n} i^{2}
257K
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
46K
det| 7 2 ; 3 8 | = 50
164K
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1