Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:53Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 5 6 ; 1 6 | = 24
52K
det| 12 5 ; 4 13 | = 136
det| 7 4 ; 4 8 | = 40
90K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 4 9 ; 7 5 | = -43
det| 4 8 ; 3 5 | = -4
137K
CH₄ + 2O₂ → CO₂ + 2H₂O
197K
∫₀^∞ e^(-α²) dα = √π / 2
196K