Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:09Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 8 ; 3 5 | = -4
244K
det| 11 9 ; 5 12 | = 87
52K
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
CH₄ + 2O₂ → CO₂ + 2H₂O
100K
det| 7 4 ; 4 8 | = 40
50K
det| 8 3 ; 4 9 | = 60
∑_{k=1}^{n} k = n(n+1)/2
137K
9x² + 3x + 6 = 0