Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:38Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∫₀^∞ e^(-φ²) dφ = √π / 2
8K
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
102K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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\oint_C \vec{F}\cdot d\vec{r} = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
276K
∇ × E = −∂B/∂t
det| 4 8 ; 3 5 | = -4
257K
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1