Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:24Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
90K
det| 9 4 ; 1 10 | = 86
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
50K
∑_{k=1}^{n} k = n(n+1)/2
137K