Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:07Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
∫₀^∞ e^(-t²) dt = √π / 2
276K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
250K
λ = h/p
\lim_{t\to 0} \frac{\sin t}{t} = 1
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 4 ; 4 8 | = 40
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
164K