Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 01:44Z
∇²γ = 0
6t² + 5t + 2 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
50K
\lim_{γ\to 0} \frac{\sin γ}{γ} = 1
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
137K
∑_{k=1}^{n} k = n(n+1)/2
197K
det| 9 4 ; 1 10 | = 86
196K