Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-φ²) dφ = √π / 2
102K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
264K
∫₀^∞ e^(-θ²) dθ = √π / 2
276K
∇ × E = −∂B/∂t
\oint_C \vec{F}\cdot d\vec{r} = 0
257K
det| 9 4 ; 1 10 | = 86
250K
λ = h/p
d/dθ [θ^7] = 7θ^6