Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 19:11Z
det| 2 5 ; 0 3 | = 6
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
9β² + 8β + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
197K
iħ ∂ψ/∂t = Ĥψ
\binom{n}{k} = \frac{n!}{k!(n-k)!}
262K
CaCO₃ → CaO + CO₂
\frac{8}{2} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0