Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:44Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
244K
det| 12 5 ; 4 13 | = 136
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
CH₄ + 2O₂ → CO₂ + 2H₂O
100K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
137K
det| 12 9 ; 5 13 | = 111
262K
∫₀^∞ e^(-t²) dt = √π / 2
196K
∑_{k=1}^{n} k = n(n+1)/2
299K