Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:29Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 7 4 ; 4 8 | = 40
52K
6ω² + 3ω + 2 = 0
det| 2 4 ; 4 3 | = -10
90K
det| 1 2 ; 7 2 | = -12
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
∑_{k=1}^{n} k = n(n+1)/2
197K
9x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
262K
9ψ² + 3ψ + 3 = 0