Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:44Z
11z² + 7z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
57K
det| 3 6 ; 6 4 | = -24
det| 7 7 ; 4 8 | = 28
264K
∑_{k=1}^{n} k = n(n+1)/2
276K
ΔS ≥ 0
det| 2 7 ; 7 3 | = -43
250K
∇²γ = 0
∑_{k=1}^{n} k = n(n+1)/2
256K