Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:09Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 12 5 ; 4 13 | = 136
∫₀^∞ e^(-ω²) dω = √π / 2
90K
∑_{k=1}^{n} k = n(n+1)/2
91K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 4 9 ; 7 5 | = -43
det| 1 1 ; 3 2 | = -1
∫₀^∞ e^(-n²) dn = √π / 2
262K