Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:36Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 9 4 ; 1 10 | = 86
100K
det| 5 3 ; 2 6 | = 24
50K