Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:00Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
52K
6ω² + 3ω + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 9 9 ; 5 10 | = 45
100K
det| 8 2 ; 7 9 | = 58
50K
det| 8 3 ; 4 9 | = 60
det| 2 6 ; 0 3 | = 6
137K
9x² + 3x + 6 = 0
∫₀^∞ e^(-n²) dn = √π / 2
196K