Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:22Z
∑_{k=1}^{n} k = n(n+1)/2
det| 8 6 ; 6 9 | = 36
244K
det| 4 8 ; 3 5 | = -4
52K
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
det| 9 4 ; 1 10 | = 86
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 3 ; 4 9 | = 60
det| 11 9 ; 0 12 | = 132
137K
det| 5 6 ; 1 6 | = 24
262K
∑_{k=1}^{n} k = n(n+1)/2
196K
∑_{k=1}^{n} k = n(n+1)/2
299K