Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:40Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
244K
det| 12 5 ; 4 13 | = 136
det| 10 3 ; 4 11 | = 98
91K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
50K
det| 4 9 ; 7 5 | = -43
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
197K
det| 1 1 ; 3 2 | = -1
∑_{k=1}^{n} k = n(n+1)/2
196K
∑_{k=1}^{n} k = n(n+1)/2
218K