Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-18 22:29Z
∂θ/∂γ = 6θ
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
428K
9γ² + 2γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
\frac{9}{8} \sum_{i=1}^{n} i^{2}
det| 8 2 ; 4 9 | = 64
\lim_{n\to 0} \frac{\sin n}{n} = 1
CaCO₃ → CaO + CO₂
E = mc²