Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:02Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
52K
6ω² + 3ω + 2 = 0
det| 11 9 ; 5 12 | = 87
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
100K
det| 8 3 ; 4 9 | = 60
det| 1 2 ; 7 2 | = -12
137K
9x² + 3x + 6 = 0