Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 14:14Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-t²) dt = √π / 2
52K
det| 12 5 ; 4 13 | = 136
det| 8 2 ; 7 9 | = 58
90K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 4 9 ; 7 5 | = -43
det| 1 1 ; 3 2 | = -1
∑_{k=1}^{n} k = n(n+1)/2
262K
det| 3 6 ; 0 4 | = 12
196K