Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:26Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-α²) dα = √π / 2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 4 6 ; 4 5 | = -4
100K
det| 8 3 ; 4 9 | = 60
∑_{k=1}^{n} k = n(n+1)/2
197K
9x² + 3x + 6 = 0
det| 5 6 ; 1 6 | = 24
218K