Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:58Z
11z² + 7z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
∑_{k=1}^{n} k = n(n+1)/2
8K
λ = h/p
d/dz [z^11] = 11z^10
102K
det| 3 6 ; 6 4 | = -24
ΔS ≥ 0
det| 9 4 ; 1 10 | = 86
257K
∑_{k=1}^{n} k = n(n+1)/2
250K
∇²γ = 0
F = G m₁m₂ / r²
CH₄ + 2O₂ → CO₂ + 2H₂O
46K
λ = h/p
\oint_C \vec{F}\cdot d\vec{r} = 0
6z² + 3z + 0 = 0