Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 18:28Z
det| 11 8 ; 0 12 | = 132
det| 5 3 ; 2 6 | = 24
244K
N₂ + 3H₂ ⇌ 2NH₃
det| 9 4 ; 1 10 | = 86
90K
det| 11 5 ; 0 12 | = 132
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
50K
CH₄ + 2O₂ → CO₂ + 2H₂O
2H₂ + O₂ → 2H₂O
d/dz [z^11] = 11z^10
262K
F = ma
ω = 2πf