Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:03Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
52K
6ω² + 3ω + 2 = 0
det| 7 4 ; 4 8 | = 40
90K
∑_{k=1}^{n} k = n(n+1)/2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-t²) dt = √π / 2
196K
det| 8 2 ; 7 9 | = 58
299K