Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:53Z
∑_{k=1}^{n} k = n(n+1)/2
6ω² + 3ω + 2 = 0
∫₀^∞ e^(-x²) dx = √π / 2
91K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 5 3 ; 2 6 | = 24
50K
det| 8 3 ; 4 9 | = 60
det| 7 4 ; 4 8 | = 40
137K
∑_{k=1}^{n} k = n(n+1)/2
197K