Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 22:33Z
11z² + 7z + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
8K
λ = h/p
\oint_C \vec{F}\cdot d\vec{r} = 0
102K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
57K
det| 3 6 ; 6 4 | = -24
\binom{n}{k} = \frac{n!}{k!(n-k)!}
276K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
257K
CH₄ + 2O₂ → CO₂ + 2H₂O
250K
∇²γ = 0
F = G m₁m₂ / r²
det| 7 4 ; 4 8 | = 40
46K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
164K
\oint_C \vec{F}\cdot d\vec{r} = 0
6z² + 3z + 0 = 0