Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:08Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
∫₀^∞ e^(-α²) dα = √π / 2
8K
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
102K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 12 9 ; 5 13 | = 111
264K
\frac{12}{7} \sum_{i=1}^{n} i^{2}
276K
∇ × E = −∂B/∂t
\binom{n}{k} = \frac{n!}{k!(n-k)!}
257K
λ = h/p
det| 9 9 ; 5 10 | = 45
62K
det| 9 4 ; 1 10 | = 86
256K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
46K
CaCO₃ → CaO + CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1