Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:11Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 2 2 ; 6 3 | = -6
det| 11 5 ; 0 12 | = 132
91K
d/dφ [φ^6] = 6φ^5
∫₀^∞ e^(-y²) dy = √π / 2
100K
det| 9 4 ; 1 10 | = 86
50K
∑_{k=1}^{n} k = n(n+1)/2
197K