Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 19:42Z
det| 2 5 ; 0 3 | = 6
AgNO₃ + NaCl → AgCl↓ + NaNO₃
52K
E = mc²
det| 9 4 ; 1 10 | = 86
91K
9β² + 8β + 1 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
100K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
iħ ∂ψ/∂t = Ĥψ
CaCO₃ → CaO + CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
218K
\frac{8}{2} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0