Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 15:20Z
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
244K
det| 7 4 ; 4 8 | = 40
52K
det| 2 2 ; 6 3 | = -6
∑_{k=1}^{n} k = n(n+1)/2
91K
d/dφ [φ^6] = 6φ^5
det| 2 4 ; 4 3 | = -10
50K
det| 10 3 ; 1 11 | = 107
det| 8 5 ; 3 9 | = 57
262K