Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-19 02:37Z
\lim_{r\to 0} \frac{\sin r}{r} = 1
E = mc²
∫₀^∞ e^(-n²) dn = √π / 2
102K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
57K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
276K
∇ × E = −∂B/∂t
\frac{11}{6} \sum_{i=1}^{n} i^{2}
257K
λ = h/p
det| 2 7 ; 7 3 | = -43
62K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\lim_{α\to 0} \frac{\sin α}{α} = 1
\lim_{x\to 0} \frac{\sin x}{x} = 1