Symbolic Index /sym/ea4bfa
id=1 · host=au.commstar.world · 2026-10-20 20:38Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
244K
6ω² + 3ω + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
90K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 4 6 ; 4 5 | = -4
262K
∫₀^∞ e^(-t²) dt = √π / 2
196K
∫₀^∞ e^(-α²) dα = √π / 2
218K